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photoshop1234 [79]
4 years ago
15

How do you divide 3.4÷12.92

Mathematics
2 answers:
Travka [436]4 years ago
8 0
Well 3.4 goes into the house and 12.92 is outside of it. 3.4 is a smaller number so you'd add zeros to get the 12.92 into 3.4. As you add zeros you'd take the decimals out and move them to the right two times. But u actually move the decimal first than adding zeros. Step 1: Take out the decimals. Step 2: Add the zeros. Step 3: Hope this helped.
777dan777 [17]4 years ago
6 0
3,4:12,92
34/10:1292/100
34/10*100/1292
34/1*10/1292
340/1292
85/323
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Which of the following inequalities is graphed above?
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Answer:

1st option

y=-3/8x+3

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Sara has to pay $10.75 a month for gym membership but will be billed yearly.how much will she pay in 5 1/2 years.
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If it's 10.75 for one month, and there are 66 months in 5 and a half years, 10.75 x 66 = $907.50
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At the bakery where you work, loaves of bread are supposed to weigh 1 pound, with a standard deviation of 0.13 pounds. You belie
saveliy_v [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

H0 : μ = 1

H1 : μ > 1

Sample size, n = 20 ; xbar = 1.05; Standard deviation, s = 0.13

Test statistic;

t because sample size is < 30

(xbar - μ) ÷ (s/sqrt(n))

(1.05 - 1) ÷ (0.13 / sqrt(20))

0.05 ÷ 0.0290688

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Using a p value calculator :

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8 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

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(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

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3 years ago
3x+4=43<br> Translate into a sentence
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