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3 years ago

Which of the following is NOT true? Question 19 options: (3x2y5)3=27x6y15 (1000x12y20z−3)0=1 52‾‾√3=523 42×43= 165

Mathematics

1 answer:

bixtya [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Lets try to simplify each to check which one is incorrect so it will be NOT true

first one is :

distribute the exponent so :

$(3x^2y^5)^3 =3^3x^{2*3}y^{5*3}$

$27x^6y^{15}$ CORRECT

Second one is :

$(1000x^{12}y^{20}z^{-30})^{0} =1$

CORRECT because anything raised to exponent 0 is 1 .

Last one is :

$4^2 *4^3 = 4^{2+3}\\=4^{6}\\=(4)^{2*3}\\=16^{3}$

so Last is INCORRECT

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Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!

Nataliya [291]

Answer:

Perimeter = 22*sqrt(2)
Area = 60.5 inches
D

Step-by-step explanation:

Remark

You need 2 facts.

A square has 4 equal sides.
It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

a^2 + a^2 = c^2
2a^2 = c^2

Givens

c = 11

Solution

2a^2 = 11^2
2a^2 = 121 Divide by 2
a^2 = 121/2 Take the square root of both sides
sqrt(a^2) = sqr(121/2)
a = 11/sqrt(2) Rationalize the denominator
a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
a = 11 * sqrt(2) / 2

Perimeter

P = 4s

P = 4*11*sqrt(2)/2
P = 44*sqrt(2)/2
P = 22*sqrt(2)

You don't need the area. The answer is D

Area

Area = s^2
Area = (11*sqrt(2)/2 ) ^2
Area = 121 * 2 / 4
Area = 60.5

8 0

3 years ago

I need help i keel putting in the correct answer and it says it wrong

Rina8888 [55]

Answer:

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6 0

3 years ago

Read 2 more answers

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

4 years ago

So this is for my geometry I'm trying to work on my review and I'm hoping that maybe one of you guys out here could help me with

alukav5142 [94]

Sorry it’s not that neat but I think the answer would be in the exact surd form root 233

7 0

3 years ago

sam went to western playland he paid $20 to get in and $5 per ride.He has a total of $50 to spend wich equation can we use to se

Leya [2.2K]

Answer:

the equation 20+5r=50 should help you see how many rides he can ride.

Step-by-step explanation:

20+5r=50

1. Subtract 20 from both sides.

5r=30

2. Divide by 5 to isolate r.

r=6

Sam can ride 6 rides.

5 0

3 years ago