A men and a women decided to meet at a certain location. If each of them independently arrives at a time uniformly between 12pm
and 1pm, find the probability that the first to arrive has to wait longer than 10 mins?
1 answer:
Answer:
the probability that the first to arrive has to wait longer than 10 mins is 35/36.
Step-by-step explanation:
First you need to denote by X and Y the time past 12 noon that the man and woman arrive.
Then you have to compute P(X+10<Y)+P(Y+10<X), which by symmetry equals 2P(X+10<Y).
So basically you have to compute P(X+10<Y).
check the attachment for the rest of the step by step.
Answer should be 25/72
But since we want 2× of the above probability 2× 25/72 = 25/36 final answer.
You might be interested in
Answer:
a.) depth of the lake = (volume of the lake) / area of lake
= 173,693,585,360,000 / 624,305,840,400 = 278.22 feet
b.) 11 inches = 0.9167 feet
Water gained in cubic feet gained by the lake
= 624,305,840,400 0.9167
= 572,282,434,719.5 cubic feet
c.) the percentage change in the lake volume over that year
= 572,282,434,719.5 cubic feet / 173,693,585,360,000 cubic feet
= 0.0033
= 0.33%
Step-by-step explanation:
i) acres to square feet : 1 acre = 43560 square feet
therefore 14,332,090 acres = 624,305,840,400 square feet
ii) 1 mile = 5280 feet
1 cubic mile = 5280 5280
5280 = 147,197,952,000 cubic feet
therefore 1180 cubic miles = 173,693,585,360,000 cubic feet
a.) depth of the lake = (volume of the lake) / area of lake
= 173,693,585,360,000 / 624,305,840,400 = 278.22 feet
b.) 11 inches = 0.9167 feet
Water gained in cubic feet gained by the lake
= 624,305,840,400 0.9167 = 572,282,434,719.5 cubic feet
c.) the percentage change in the lake volume over that year
= 572,282,434,719.5 cubic feet / 173,693,585,360,000 cubic feet
= 0.0033
= 0.33%