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amm1812
3 years ago
6

A men and a women decided to meet at a certain location. If each of them independently arrives at a time uniformly between 12pm

and 1pm, find the probability that the first to arrive has to wait longer than 10 mins?

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

the probability that the first to arrive has to wait longer than 10 mins is 35/36.

Step-by-step explanation:

First you need to denote by X and Y the time past 12 noon that the man and woman arrive.

Then you have to compute P(X+10<Y)+P(Y+10<X), which by symmetry equals 2P(X+10<Y).

So basically you have to compute P(X+10<Y).

check the attachment for the rest of the step by step.

Answer should be 25/72

But since we want 2× of the above probability 2× 25/72 = 25/36 final answer.

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<h3>How to determine the domain of g(x)?</h3>

The function is given as:

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Since f(x) is a function, then g(x) is also a function

The domain of f(x) is given as:

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2 years ago
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5 0
2 years ago
An insurance company pays Tommy a $400 commission for selling a $100,000 insurance policy. At this rate, what would be Tommy’s c
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Step-by-step explanation:

He gets paid a commission of $400 for a $100,000 insurance policy. We need to find out how much he's gonna get paid for a $25,000 insurance policy.


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$25,000

$25,000

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Now break down his commission of $400 for the $100,000 insurance policy into four equal amounts if possible, which it is:

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3 years ago
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