Answer:
a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

Where a and b represent the limits of the distribution.
b) 
And the height for this case would be 0.125
Step-by-step explanation:
Part a
For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

Where a and b represent the limits of the distribution.
Part b
For this case the density function would be given by:

And the height for this case would be 0.125
And
for other case.
The cumulative distribution function would be given by:



Answer:
<h3>lt = lo/cos²θ</h3>
Step-by-step explanation:
Given the intensity of the transmitted light It and θ are related by the equation Cosθ= √ Io/It, we are to write lt as a function of lo
Given the equation
Cosθ= √ Io/It
Let us make lt the subject of the formula;
square both sides of the equation
(Cosθ)²= (√ Io/It)²
cos²θ = lo/lt
cross multiply
ltcos²θ = lo
divide both sides by cos²θ
ltcos²θ/ cos²θ= lo/cos²θ
lt = lo/cos²θ
Hence the expression of lt as a function of lo is lt = lo/cos²θ
Answer:
2/3
Step-by-step explanation:
The slope is 2/3 because when using the rise over run formula
your rise would be 2 and the run would be 3
Step-by-step explanation:
eliminăm parantezele:
a²+16a+64-(12b+60)
calculăm:
a²+16a+64-12b-60
Rezultatul:
a²+16a+4-12b