Answer:
Step-by-step explanation:
Step one:
given
expected weight= 28pounds
Actual weight= 25 pound
Required:
percent error
δ= percent error
vA =actual value observed
vE =expected value
δ=25-28/28*100
δ=-3/28*100
δ=0.107*100
δ=10.7%
The percent error is 10.7%
Given
Length of rectangle is
Perimeter must be greater than 40 ft
Suppose l and w be the length and width of the rectangle
So, the smallest width can be
True
i think it would be 2 degrees every hour for 10 to 11 hours i think it would be 2 degrees