I believe it would be (b) (-2,1)
Answer:
The rule used to reflect Δ ABC to its image is Reflect over y = x ⇒ B
Step-by-step explanation:
- If the point (x, y) reflected across the x-axis
, then its image is (x, -y)
- If the point (x, y) reflected across the y-axis
, then its image is (-x, y)
- If the point (x, y) reflected across the line y = x
, then its image is (y, x)
- If the point (x, y) reflected across the line y = -x
, then its image is (-y, -x)
From the given figure
∵ The coordinates of point A are (-4.5, 6)
∵ The coordinates of point A' are (6, -4.5)
→ The coordinates are switched ⇒ 3rd rule
∴ Point A is reflected over the line y = x
∴ Δ ABC is reflected over the line y = x
∴ The rule used to reflect Δ ABC to its image is Reflect over y = x
<em>Note: Point B' on the graph should be C' and point C' should be B' (correct it)</em>
Answer:
Therefore either a:b = 5:4 or a:b=-5:4
Step-by-step explanation:
ax²-5bx+4a=0
Since the quadratic equation has two real root.
Then b²-4ac>0
Here a= a , b= -5b and c=4a
∴(-5b)²-4.a.4a=0
⇔25b²=16a²
⇔5b=±4a
Therefore either a:b = 5:4 or a:b=-5:4
