What is the area of a triangle with vertices at (−2, 1), (2, 1), and (3, 4) ?
1 answer:
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Answer:
y= -2/3x-2
Step-by-step explanation:
Since we have a point and a slope, we can use the point slope formula
m is the slope. In this case, m is -2/3
y1 is the y coordinate of the point. In this case, it is -2
x1 is the x coordinate. In this case it is 0.
We can substitute these values into the formula
y- -2= -2/3(x-0)
Distribute -2/3
y+2 = -2/3*x + -2/3*0
y+2= -2/3x+0
Subtract 2 from both sides. We want to get y by itself. This is because we want our line to be in y=mx+b form.
y+2-2= -2/3x+0-2
y= -2/3x -2