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Vitek1552 [10]
3 years ago
13

What is the area of a triangle with vertices at (−2, 1), (2, 1), and ​(3, 4)​ ?

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

6 Units.

Step-by-step explanation:

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Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn
My name is Ann [436]
\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
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c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
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c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
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c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2
7 0
4 years ago
PLEASE HELP on number 3
solmaris [256]

Answer16

Step-by-step explanation:

5 0
4 years ago
Pls Help! 100 Points!!!<br> Show all work to factor x^4 − 5x^2 + 4 completely.
Amiraneli [1.4K]

Answer:

(x+2)(x-2)(x+1)(x-1)

Step-by-step explanation:

We want to factor the expression x^4-5x^2+4.

First, notice that this is in quadratic form. In other words, both the exponents have even power.

Therefore, we can make a substitution to simplify the expression.

So, let’s let u=x^2.

Our expression is the same as:

(x^2)^2-5(x^2)+4

Substitute:

u^2-5u+4

Now, we can factor like normal. We can use -1 and -4. Therefore:

=(u-4)(u-1)

We can now substitute back u:

=(x^2-4)(x^2-1)

Both of these can be factored furthered using the difference of two squares:

(a^2-b^2)=(a+b)(a-b)

Therefore, we will have:

=(x+2)(x-2)(x+1)(x-1)

And we are done!

6 0
3 years ago
How to prove system of nonlinear equations has finite solutions?
nalin [4]
This is what you could do

4 0
3 years ago
The table shows the record low temperatures for several states. Graph the temperatures on a number line.
OlgaM077 [116]

Step-by-step explanation:

Please find the attachment.

We have been given a table that shows the record low temperatures for several states. We are asked to graph the temperatures on a number line.

First of all we will draw a number line going to infinity into both directions.  

To graph the given temperatures on number line let us arrange temperatures in less negative order.  

-34, -32, -30, -29, -27.  

Since we know that numbers with large negative values lie on the left at number line. Let us graph our large negative temperature on the left at our number line.      

We can see that -34 is the most negative temperature, therefore, it will be on the left most side of our number line.  

-27 is greatest of our given negative temperatures. -27 is less negative temperature than our other given low temperatures, therefore, it will lie on the right most side of our number line.  

Other temperatures will lie between these two values according to their temperatures.    

-32 is second large negative temperature after -34, therefore, it will lie on the right side of -34.

-30 will lie on the right side of -32 and -29 will lie on the right of -32.


4 0
3 years ago
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