Answer:
10 m
Explanation:
The mole fraction of FeCl₃ of 0.15, that is, per mole of solution, there are 0.15 moles of FeCl₃ and 1 - 0.15 = 0.85 moles of water.
The molar mass of water is 18.02 g/mol. The mass corresponding to 0.85 moles is:
0.85 mol × 18.02 g/mol = 15 g = 0.015 kg
The molality of FeCl₃ is:
m = moles of solute / kilogram of solvent
m = 0.15 mol / 0.015 kg
m = 10 m
I believe the answer is b but im not 100% sure
Answer:
5
Explanation:
Let us look at the values very closely. It is easy to see that the first to the fifth ionization energies of the element are closely related to each other. Recall that the ionization energy increases as the the number of electrons removed from the outermost shell of the atom increases. Hence E1<E2<E3......... The first five ionization energies suggest the removal of valence shell electrons.
However, the sixth and seventh ionization energies shows a jump, the ionization energy suddenly increases by a very high magnitude. This can not suggest the removal of a valence shell electron but the removal of inner or core electrons. Hence the answer.
<u>Given:</u>
Concentration of Na₂S = 0.765 M
Volume of Na₂S solution = 25.0 ml = 0.025 L
Final total volume = 225 ml = 0.225 L
<u>To determine:</u>
The concentration of Na+ ions
<u>Explanation:</u>
# moles of Na₂S = 0.765 * 0.025 = 0.0191 moles
Based on the atomic stoichiometry of Na₂S-
# moles of Na⁺ ions = 2*0.0191 = 0.0382 moles
conc of Na⁺ ions = 0.0382 moles/ 0.225 L = 0.169 M
Ans: [Na⁺] = 0.169 M
I THINK this is the answer: 4809.35999999786. (found it on a website)
