The structure is in attachment.
Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds<span> are </span>single) <span>of six </span>carbon atoms. Methoxy<span> group is the functional group consisting of a methyl group bound to oxygen. Iodo is substituent consists of ionide (element in 17 periodic group).</span>
The correct matches are as follows:
<span>1.instantaneous combustion
</span>G.burning<span>
2.mass of substances before and after a reaction is the same
</span>C.Law of Conservation of Matter<span>
3.substances that combine
</span>A.reactants
<span>
4. Yields or makes
</span>B.arrow symbol
<span>
5.rapid oxidation
</span>F.explosion<span>
6.new substance
</span>D.product
<span>
7.slow oxidation
</span>E.rust
<span>
Hope this answers the question. Have a nice day.
</span>
Answer:
Place 20.0 g NaOH(s) in a flask and dilute to 1.00 L with water.
Explanation:
More particles collide in the correct orientation
Answer:
Explanation:
Let A₀ = the original amount of ⁵⁵Co
.
The amount remaining after one half-life is ½A₀.
After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.
After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀.
The general formula for the amount remaining is:
A =A₀(½)ⁿ
where n is the number of half-lives
n = t/t_½
Data:
A = 1.90 ng
t = 45 h
t_½ = 18.0 h
Calculation:
(a) Calculate n
n = 45/18.0 = 2.5
(b) Calculate A
1.90 = A₀ × (½)^2.5
1.90 = A₀ × 0.178
A₀ = 1.90/0.178 = 10.7 ng
The original mass of ⁵⁵Co was .
