The question is incomplete, here is the complete question.
A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of copper fluoride in the solution is 
<u>Explanation:</u>
To calculate the molarity of solute, we use the equation:

We are given:
Given mass of copper (II) fluoride = 0.0498 g
Molar mass of copper (II) fluoride = 101.54 g/mol
Volume of solution = 100.0 mL
Putting values in above equation, we get:

Hence, the concentration of copper fluoride in the solution is 
Answer:

Explanation:
The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:
Chemical equation: 
Balance H and O in basic medium: 
Balance charge: 
Balanced chemical equation:

0,26mol ------- 13g
1mol ------- x
x = (13g*1mol) / 0,26mol = 50g
It could be Ti or V
Answer:
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