Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q =
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S = 
048° + 0
+ <S = 
+ <S = 
<S =
- 
= 
<S = 
Applying the Sine rule,
=
= 
= 
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
= 
= 
= 
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Answer:
X=96
Step-by-step explanation:
180-134=46
180-130=50
SUM OF TWO INTERIOR ANGLES = EXTERIOR ANGLE
50 + 46=96
The 32,500 is the original cost of the truck and the (0.92) You take v(x)=32,500(0.92)
and raise that to the 2nd power, to represent the 2nd year and you will get an answer of $27,300.
Each year the truck is losing $2,600 in value, after two years the truck has lost $5,200 in value equalling
= $27,300