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Gemiola [76]
3 years ago
14

I need help with this ​

Mathematics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

-3x+2y greater than or equal to 7

Step-by-step explanation:

we can take away the first and second cause the line is full and not dotted. with desmos, i plugged the equation in and found that the third equation matches the picture

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Drawing it out would be best can you help me please
leva [86]

Answer:

z_1+z_2 = (-2,5)

Step-by-step explanation:

To Find: z_1+z_2

Solution :

Referring the given graph

We can find the coordinates of   z_1 and  z_2

Coordinates of   z_1= (-7,1)

Coordinates of  z_2= (5,4)

Thus Coordinates of  z_1+z_2 = (-7+5,1+4) = (-2,5)

Thus z_1+z_2 = (-2,5)

So, the point z_1+z_2 = (-2,5) is shown on the attached graph file

6 0
3 years ago
If f(x) = x-9, then f '(x) =​
erica [24]

Answer:

1

Step-by-step explanation:

If you are just looking for the derivative, then all you need to use the power rule for this. Technically the x in (x-9) has a power to the 1, so really x^1-9. To use power rule, you bring down the exponent, in this case, 1, and then minus 1 from what the exponent was.

1x^(1-1) = 1x^0. The derivative of any constant is 0, so don't even worry about the -9. We know that anything raised to the zero is just 1, so in this case your answer is 1.

Hope this helps :)

4 0
3 years ago
(9x2 + 10x + 4) − (9x2 + 5x − 1)
ch4aika [34]

For this case we must simplify the following expression:

(9x ^ 2 + 10x + 4) - (9x ^ 2 + 5x-1)

We eliminate the parentheses taking into account that:

- * + = -\\- * - = +\\9x ^ 2 + 10x + 4-9x ^ 2-5x + 1 =

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

9x ^ 2-9x ^ 2 + 10x-5x + 4 + 1 =\\5x + 5

Answer:

5x + 5

3 0
3 years ago
Malik buys and sells car parts. He bought two tires for $45.00 each and later sold them for $65.00 each. He bought three rims fo
Alona [7]
The answer is $213 because you subtract the price sold by the price he bought them for and then you add them together (see work)

6 0
3 years ago
Read 2 more answers
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
2 years ago
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