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mote1985 [20]
3 years ago
11

Some 1 plz HELP! 3 5/6 X 4 4/5 (plz include instructions if u can thx!)

Mathematics
2 answers:
rewona [7]3 years ago
8 0
Well convert 3 5/6 to 23/6 and 4 4/5 to 24/ 5
then find a multiple that both 5 and 6 have which is 30
23x5= 115 and 24x6= 144
so 115 x 144= 16560/30
16560/30 = 552 /1 so your answer is 
552
True [87]3 years ago
7 0
Exact Form: 92/5
Decimal Form: 18.4
Mixed Number Form: 18 2/5

Multiply the denominator and the whole number and add the numerator. Do the same for the other problem and then add them both together!
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A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

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Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

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N''(t) = 20(2+\frac{2}{t^2})

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N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

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N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

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