3 years ago

At the pet store the ratio of dogs to cats was 4:7. For every dogs there are cats.

1 answer:

topjm [15]3 years ago

6 0

so for every 4 dogs, there are 7 cats. You could replace this with 8 dogs to 14 cats (you're doubling both).

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Stels [109]

Answer:

Step-by-step explanation:

If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8

The engine speed is at maximum if dy/dx = 0

dy/dx = -2(3.75)x+23.2

dy/dx = -7.5x + 23.2

since dy/dx = 0

0 = -7.5x + 23.2

7.5x = 23.2

x = 23.2/7.5

x = 3.093

Hence the maximum torque is 3.09 rev/min

8 0

3 years ago

blsea [12.9K]

B hope it helps have a good day

6 0

3 years ago

DaniilM [7]

The answer would be 10 since 10 times 5 is 50 and a line equals 180 so the answer is A.10

5 0

3 years ago

Vaselesa [24]

The answer is

2. 2a+12

Show work

2a+7+2a+7+4+4= 4a+22

A+2+a+2+3+3 = 2a+10

(4a+22)-(2a+10) = 2a+12

6 0

3 years ago

Akimi4 [234]

Should be 4 for B because 8-4 would equal 4

7 0

3 years ago

At the pet store the ratio of dogs to cats was 4:7. For every __ dogs there are __ cats.