<img src="https://tex.z-dn.net/?f=%285%20%7By%7D%5E%7B2%7D%20%20%2B%20y%20%2B%206%29%20%2B%20%28%20%7By%7D%5E%7B2%7D%20%20%2B%20

3 years ago

11y%20-%206%29" id="TexFormula1" title="(5 {y}^{2} + y + 6) + ( {y}^{2} + 11y - 6)" alt="(5 {y}^{2} + y + 6) + ( {y}^{2} + 11y - 6)" align="absmiddle" class="latex-formula">
solve

Mathematics

1 answer:

Pie3 years ago

6 0

Answer:

$6y^2+12y$

Step-by-step explanation:

$\left(5y^2+y+6\right)+\left(y^2+11y-6\right)$

remove parentheses

$\left5y^2+y+6\right+\lefty^2+11y-6\right\\$

add like terms

$6y^2+12y+6-6\\$

simplify

$6y^2+12y$

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Let f(x) = -2x - 7 and g(x) = -4x + 6. Find (fxg)(-5). a. -59 b. 3 c. 26 d. -6

DedPeter [7]

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3 years ago

If -2x+3=7 and 3x+1= 5+y

sertanlavr [38]

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Step-by-step explanation:

solve for x first in the equation -2x+3=7

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now plug that x value into the other equation so we can find y

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3 years ago

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