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Marizza181 [45]
3 years ago
13

Use the diagram below to Identify pairs of angles that are​

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

alternate interior। 4a and 1b

alternate exterior 3b and 3a

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4x + 2 &lt; 2x + 9<br> Which graph shows the solution of the<br> inequality?
Savatey [412]

Answer:

i am pretty sure it's B correct me if i am wrong

Step-by-step explanation:

7 0
3 years ago
What is the minimum cuts<br> needed to cut a circle into 8<br> equal parts?
Gnom [1K]

What is the minimum cuts  needed to cut a circle into 8  equal parts ?

A : 4 cuts

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3 years ago
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2oz+2.5lbs+1/4lbs= <br> How do I find the answer
Anton [14]
Well you have to convert the pounds to ounces
1 pound = 16 ounces
2oz+40oz+4oz
46oz
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3 years ago
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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
Can you help me find the value of x and y. I am very confused.
Monica [59]
Hello,
Let's assume top left  corner: A
top right corner : B
Bottom right corner: C
Bottom left corner :D

M= middle of [CD]

ABM is a triangle rectangular isocel:

(3√2)²+(3√2)²=y²
==>y²=2*9*2
==>y²=36
==>y=6

The triangle BCM is rectangular with MB=3√2, MC=y/2=3
x²+3²=(3√2)²
==>x²=9*2-9
==>x²=9
==>x=3

8 0
3 years ago
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