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Marizza181 [45]
3 years ago
13

Use the diagram below to Identify pairs of angles that are​

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

alternate interior। 4a and 1b

alternate exterior 3b and 3a

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An architect in Brussels measures something to be 2.5 feet (using the Brussels measurement). How many feet is this in Aalst (usi
borishaifa [10]

Answer:

2.487F

Step-by-step explanation:

From the question we are told that

Architect Measures 2.5 feet (using the Brussels measurement)

Generally in Brussels  1F=275.75mm

Therefore

    2.5F=689.375mm

Generally in Aalst 1F=277.2mm

Therefore Mathematically converting  to feet in Aalst measurement we get

    689.375mm*\frac{1}{277.2} =2.487F

   

6 0
3 years ago
What is the standard form of the linear function that passes
babunello [35]

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{4}}}\implies \cfrac{-3}{-2}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{4})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(y-1)=2\left( \cfrac{3}{2}(x-4) \right)}\implies 2y-2 = 3(x-4)\implies 2y-2=3x-12 \\\\\\ -3x+2y-2=-12\implies -3x+2y=-10\implies \stackrel{\times -1\textit{ to both sides}}{3x-2y=10}

7 0
2 years ago
What's a pair of equal ratios
Kruka [31]
Y= 2x + 2 and y= 2x - 1
8 0
3 years ago
A line segment has the endpoints P(0, –6) and Q(–3, –7). Find the coordinates of its midpoint M.
rewona [7]

Answer:

i dont know.

Step-by-step explanation:

pls make it brainliest

5 0
2 years ago
At 4:00 am, the outside temperature was -28*F. By 4:00 P.M. it rose 38 degrees. What was the temperature at 4:00 P.M. ?
andreyandreev [35.5K]
The answer would be 10 degrees
i hope this helps
7 0
3 years ago
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