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vaieri [72.5K]
3 years ago
7

The recursive rule for a sequence and one of the specific terms is given. Find the position of the given

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

6th term

Step-by-step explanation

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Pls, help!!!! Will make brainliest!!!
riadik2000 [5.3K]

Answer:

y=2x+6

Step-by-step explanation:

slope intercept formula → y=mx+b

\frac{6-2}{0-(-2)} =\frac{4}{2} =2\\

so 2 is your slope and the point (0,6) crosses the y-intercept at 6 since x = 0

plugin 2 for m (or the slope) and 6 for b (y-intercept)

your answer → y=2x+6

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2 years ago
Find the value for y.
Elena L [17]
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good luck
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3 years ago
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Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
3 years ago
What is the rule for the reflection?
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<span>Reflection in the line y = x. A reflection in the line y = x can be seen in the picture below in which A is reflected to its image A'. The general rule for a reflection in the y-axis: (A, B) (B, A)</span>
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Step-by-step explanation:

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