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IceJOKER [234]
4 years ago
15

The radius of the unit circle is equal to

Mathematics
2 answers:
maksim [4K]4 years ago
3 0

Answer:

The unit circle is a circle with a radius of 1.

This means that for any straight line drawn from the center point of the circle to any point along the edge of the circle, the length of that line will always equal 1

Step-by-step explanation:

evablogger [386]4 years ago
3 0

The unit circle is a circle with a radius of 1.

This means that for any straight line drawn from the center point of the circle to any point along the edge of the circle, the length of that line will always equal 1.

I hope this helps you.

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7 eighths plus 1 fourth
masha68 [24]
7\cdot \frac { 1 }{ 8 } +\frac { 1 }{ 4 } \\ \\ =7\cdot \frac { 1 }{ 8 } +\frac { 2 }{ 8 }

\\ \\ =\frac { 1 }{ 8 } \left( 7+2 \right) \\ \\ =\frac { 1 }{ 8 } \cdot 9\\ \\ =\frac { 9 }{ 8 }
6 0
3 years ago
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A 0. 0427 kg racquetball is moving 22. 3 m/s when it strikes a stationary box. The ball bounces back at 11. 5 m/s, while the box
andreyandreev [35.5K]

To solve the question we must know about the conservation of momentum.

<h2>Conservation of Momentum</h2>

According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.

the momentum of the two objects before the collision

                       = momentum of the two objects after the collision

The mass of the box is 0.30141 kg.

<h2>Explanation</h2>

Given to us

  • Mass of racquetball, m = 0.0427 kg,
  • Velocity of racquetball before Collision,  \bold{u_1} = 22.3 m/s,
  • Velocity of box before Collision,\bold{ u_2}  = 0 m/s,
  • Velocity of racquetball after Collision, \bold{v_1} = 11.5 m/s,
  • Velocity of box after Collision, \bold{v_2} = 1.53 m/s,

<h3>Assumption</h3>

Let the mass of the box be M.

<h3>Conservation Of Momentum</h3>

Momentum before collision = Momentum after collision

mu_1 + Mu_2 = mv_1 + Mv_2

given, the box was stationary before the collision,

mu_1 + Mu_2 = mv_1 + Mv_2\\\\&#10;mu_1 + 0 = mv_1 + Mv_2\\\\&#10;mu_1  - mv_1 = Mv_2\\\\&#10;M= \dfrac{mu_1  - mv_1}{v_2}

Substituting the values,

M= \dfrac{mu_1  - mv_1}{v_2}\\\\&#10;M = \dfrac{(0.0427 \times 22.3)  - (0.0427\times 11.5)}{1.53}\\\\&#10;M = 0.30141\ kg

Hence, the mass of the box is 0.30141 kg.

Learn more about Conservation of Momentum:

brainly.com/question/2141713

3 0
3 years ago
A population of fish starts at 8,000 and decreases by 6% per year. what is the population of fish after 10 years?
ladessa [460]

Answer:

4308 fish

Step-by-step explanation:

Well you can just look at the answer and tell

14327 is not possible at all, thats an increase

839 is way too low

7680 doesn't make sense at all

4,309 is the most reasonable

6 0
3 years ago
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Which sequence can be generated from the formula f(x + 1) = One-half(f(x))?
AlekseyPX

Answer:

x, StartFraction x Over 2 EndFraction, StartFraction x Over 4 EndFraction, StartFraction x Over 8 EndFraction, ellipsis

Step-by-step explanation:

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3 years ago
Solve for x.<br> 112°<br> (5x - 3)°<br> (4x + 16)°
ANTONII [103]

Answer:

11

Step-by-step explanation:

180 - 112 = 68

4x + 16 +5x - 3 + 68 = 180

simplify.

9x + 81 = 180. subtract 81 from 180

9x = 99. divide 99 by 9

x = 11.

8 0
3 years ago
Read 2 more answers
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