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laila [671]
3 years ago
14

Devi and her brother had the same amount of money. After Devi spent 2/5 of her money and her brother spent 3/10 on his money, th

ey had 78$ left
altogether. How much money did they spend altogether?
Mathematics
1 answer:
xeze [42]3 years ago
5 0

Let us assume Devi or her brother amount = $x.

Devi spent 2/5 of x, that is 2/5 x.

Remaining amount of Devi = x- 2/5 x = 5x/5 - 2x/5 = 3x/5.

Her brother spent 3/10 of x, that is 3/10 x.

Remaining amount of her brother = x- 3/10 x = 10x/10 - 3x/10 = 7x/10.

Total amount they left together = $78.

Therefore, 3x/5\:+\:7x/10\:=\:78\:

\frac{3x}{5}+\frac{7x}{10}=78

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}5,\:10:\quad 10

Multiply equation by LCM 10.

\frac{3x}{5}\cdot \:10+\frac{7x}{10}\cdot \:10=78\cdot \:10

6x+7x=780

13x=780

\mathrm{Divide\:both\:sides\:by\:}13

\frac{13x}{13}=\frac{780}{13}

x=60

<h3>Therefore, each one spent $60 and they spent altogether = 60+60 = $120.</h3>

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