3 years ago

Please help me, 6th grade math

Mathematics

1 answer:

Stells [14]3 years ago

5 0

Answer:

Mean: 3.2 Median: 3.2 Mode:3.1 Range:0.5

Step-by-step explanation:

Easy.

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PLEASE HELP? I need help ASAP heh.

spayn [35]

Answer:

5/12

Step-by-step explanation:

12 total squares

5 shaded

5shaded to 12 total

5:12

5/12

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2 years ago

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What is 34/51 in its simplest form

sveticcg [70]

2/3
divide by 17

34/17 is 2
51/17 is 3

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3 years ago

Write the equation of a line that is perpendicular to y=-2/7x + 9 and that passes through the point (-4,6) [FP]

siniylev [52]

Answer:

$y=(7/2)x+20$

Step-by-step explanation:

SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.

Therefore by the point slope formula the line that we are looking for is

$y-6=(7/2)(x+4)$

$y=(7/2)x + 20$

7 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

What is the value of x in the equation 8x – 2y = 48, when y = 4?

morpeh [17]

Answer:

x = 7

Step-by-step explanation:

since we know y = 4, we can plug this into the equation to find x

8x - 2y = 48

8x - 2(4) = 48

8x - 8 = 48

8x = 56

x = 7

4 0

3 years ago

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