Question

Determine where f(x) = x2 + 2x - 8 intersects the x-axis.

Answer 1

Let f(x) =0.
${x}^{2} + 2x - 8 = 0 \\ (x + 4)(x - 2) = 0 \\ x + 4 = 0 \\ x = - 4 \\ x - 2 = 0 \\ x = 2$
x=-4, 2