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Ksju [112]
3 years ago
6

How do I find the center & radius, then write a standard equation for a,b, and c?

Mathematics
1 answer:
Ghella [55]3 years ago
5 0

Firstly , we will locate centres and radius in the figures

(a)

We can see that

centre=(h,k)=(0,0)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

(b)

We can see that

centre=(h,k)=(5,4)

radius=r=3

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-5)^2+(y-4)^2=3^2

(x-5)^2+(y-4)^2=9

(c)

We can see that

centre=(h,k)=(4,3)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-4)^2+(y-3)^2=5^2

(x-4)^2+(y-3)^2=25


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3 years ago
Someone solve this quick please
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3 years ago
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IrinaVladis [17]
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6 0
3 years ago
Construct a linear function, f(x), to model the ordered pairs (6, 2) and (7, −5). f(x) = 7x + 44 f(x) = x + 4 f(x) = −44x + 7 f(
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First we find the slope between the two given points.

m = (y2 - y1)/(x2 - x1) = (-5 - 2)/(7 - 6) = -7/1 = -7

Now we use the slope-intercept equation of a line.

y = mx + b

We use one point as x and y, and we solve for b.

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4 years ago
Work out the area of the trapezium ABDE.<br> B<br> 9 cm<br> 6 cm<br> 8 cm<br> →D<br> E
Evgen [1.6K]

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

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\frac{AE}{BD}= \frac{CE}{CD}

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CE = \frac{9\times 8}{6}

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Therefore, DE = CE - CD

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Now area of trapezium ABDE = \frac{1}{2}(AE+BD)(DE)

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                                                  = 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

8 0
3 years ago
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