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denpristay [2]
3 years ago
15

What is the 10th term of the following geometric sequence?

Mathematics
1 answer:
GaryK [48]3 years ago
8 0
An find the common ratio by dividing the second term by the first term
(-7/3) / (7/9) = -7/3 * 9/7 = -21/7 reduces to -3 <== common ratio

an = a1 * r^(n - 1)
n = term to find = 10
a1 = first term = 7/9
r = common ratio = -3

now we sub
a10 = 7/9 * -3^(10 - 1)
a10 = 7/9 * -3^9
a10 = 7/9 * -19683
a10 = - 137781 / 9
a10 = - 15309 <==


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Find the sum or difference answers

1. Simplify or expand
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2. Simplify or expand
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8 0
3 years ago
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Salsk061 [2.6K]

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8 0
3 years ago
How do you solve the system:<br> y+1=2x<br> 5y+5=10x
Marta_Voda [28]

Answer:

choose "infinitely more solutions"

Step-by-step explanation:

Let's solve this system by substitution method

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- 1 = - 1

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4 0
3 years ago
Read 2 more answers
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