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vfiekz [6]
3 years ago
7

What are the solutions of the quadratic equation? 2 x 2 – 16 x + 32 = 0

Mathematics
2 answers:
shusha [124]3 years ago
5 0

Answer: x = 4 twice

Step-by-step explanation:

The given quadratic equation is expressed as

2x^2 - 16x + 32 = 0

Dividing the left hand side and the right hand side of the equation by 2, it becomes

x^2 - 8x + 16 = 0

We would find two numbers such that their sum or difference is -8x and their product is 16x^2. The two numbers are - 4x and - 4x. They,

x^2 - 4x - 4x + 16 = 0

x(x - 4) - 4(x - 4) = 0

x - 4 = 0 or x- 4 = 0

x = 4 twice

Evgen [1.6K]3 years ago
3 0

Answer:

4 - 16 x + 32 = 0

- 16 x = - 4 - 32

- 16 x = - 36

X = 2.25

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HURRY PLEASE <br><br> What is the solution of the system 4x+3y=6 2x+2y=5
jolli1 [7]
The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I

The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II

Substitute with equation II in equation I to get the value of y as follows:
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x = -3/2
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7 0
3 years ago
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The function f(x) = square root -x is shown on the graph. Which statement is correct?
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Answer:

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Answer:

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