we know that
A half-acre is equal to----------> 
Let
x---------> the length side of the building lot
y--------> the width side of the building lot
A------> Area of the building lot
x=5y-------> equation 1
--------> equation 2
substitute equation 1 in equation 2
![2,023.43=[5y]*y](https://tex.z-dn.net/?f=2%2C023.43%3D%5B5y%5D%2Ay)
<u>Find the value of x</u>
therefore
<u>the answer is</u>
the dimensions of the building lot are 100.55 m* 20.11 m
Answer:
1.1
Step-by-step explanation:
4.5 to 6.5 i think not really shure
Answer:
The answer is D. -5.
Step-by-step explanation:
The sequence begins with 9. The sequence is reduced by 2 each step, for seven steps. Results of the seven negative steps:
7 * -2 = -14.
The difference is:
9 - 14 = -5
![\bf \textit{sum of all interior angles in a polygon}\\\\ n\theta = 180(n-2)~~ \begin{cases} n = sides\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ n= 100 \end{cases}\implies \theta 100=180(100-2) \\\\\\ 100\theta = 180(98)\implies 100\theta =17640\implies \theta =\cfrac{17640}{100}\implies \theta = \cfrac{882}{5}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsum%20of%20all%20interior%20angles%20in%20a%20polygon%7D%5C%5C%5C%5C%20n%5Ctheta%20%3D%20180%28n-2%29~~%20%5Cbegin%7Bcases%7D%20n%20%3D%20sides%5C%5C%20%5Ctheta%20%3Dangle~in%5C%5C%20%5Cqquad%20degrees%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20n%3D%20100%20%5Cend%7Bcases%7D%5Cimplies%20%5Ctheta%20100%3D180%28100-2%29%20%5C%5C%5C%5C%5C%5C%20100%5Ctheta%20%3D%20180%2898%29%5Cimplies%20100%5Ctheta%20%3D17640%5Cimplies%20%5Ctheta%20%3D%5Ccfrac%7B17640%7D%7B100%7D%5Cimplies%20%5Ctheta%20%3D%20%5Ccfrac%7B882%7D%7B5%7D)
which is pretty much just 176.4°, well, we also know that θ = 3x + 26.4
