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3 years ago

Find the values of x and y plz

Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

Answer:

x= 40, y= 140

Step-by-step explanation:

if two parellel lines cut by a transversal then same-side interior angles are supplementary.

180-140 = x

x = 40

x and y are suplementary

180-40 = 140

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elixir [45]

Answer:

The perimeter is 22.

Step-by-step explanation:

If you turn this shape into a rectangle, the perimeter doesn't change.

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3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

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Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

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The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

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3 years ago

20 and 23 lcm and gcf

liraira [26]

Answer:

GCF: 1

LCM: 460

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3 years ago

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30 POINTS HELP PLEASE

Reptile [31]

Answer:

$\large\boxed{a=-3,\ b=-7\ and\ c=3}$

Step-by-step explanation:

$ax^2+bx+c=0$

We have:

$-3a^2=7a-3$ subtract 7a from both sides

$-3a^2-7a=7a-7a-3$

$-3a^2-7a=-3$ add 3 to both sides

$-3a^2-7a+3=-3+3\\\\-3a^2-7a+3=0\to a=-3,\ b=-7, c=3$

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4 years ago

Which value of X is a solution of x<-2 A.-3 B.-2 C.-1 D.0

iren [92.7K]

Answer:

A.) -3

Step-by-step explanation:

-3 is less than -2 therefore, it fits the answer.

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3 years ago

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