The answer is...
three and seventy five hundredths
Answer:
8900000 * 10^-3
Step-by-step explanation:
(8.9*10^-3)/(10^-6)
(8.9*10^-3)/(1/1000000)
8.9*10^-3* 1000000
8900000 * 10^-3
Times the sides and add them
The factored expression which represents the net change in the number of blog subscriptions over 10 months is :
- 3(11 - 7) + 4(-8)
- Hence, the net change is -20
Change : -8, 11, -7, -7, -7, -8, -8, -8, 11, 11
To factor the values in the change variable :
-7 has a frequency of 3
-8 has a frequency of 4
11 has a frequency of 3
Values having the same frequency can be factored together :
Hence, we have ;
3(11 - 7) = 3(11 - 7) = 3(4) = 12 - - - - (1)
-8 having a value of 4 can be factored thus ; 4(-8) = -32 - - (2)
Joining both equations :
3(11-7) + 4(-8)
3(11 - 7) + 4(-8)
3(4) + 4(-8)
12 + (-32)
= - 20
Therefore, the factored expression for the net change in subscription is 3(11-7) + 4(-8)
Learn more :brainly.com/question/18904995
I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is
