Which of the following statements identifies and explains whether the two triangles are similar?

Mathematics

2 answers:

nata0808 [166]2 years ago

7 0

Answer:

I think it's "C"

the triangles are nor similar because the variables x and y have different values.

P.S. hope it helped. If you have any questions, I'll be glad to answer them❤

olya-2409 [2.1K]2 years ago

5 0

Answer:

it's "C"

Step-by-step explanation:

the triangles are nor similar because the variables x and y have different values.

You might be interested in

What is the midpoint of the segment shown below?

melomori [17]

Answer:

B is the right answer

4 0

2 years ago

A.Find the total and area of the compound figures

goldfiish [28.3K]

Answer:

(a) The total area of compound figure is $284.52ft^2$ .

(b) The total perimeter of compound figure is 68.84 ft.

Step-by-step explanation:

Perimeter: The total distance covered by the figure.

Area: It is defined as the space occupied by the figure.

Given:

Length of rectangular figure = 19 ft

Breadth of rectangular figure = 12 ft

Radius of circle, r = $\frac{12ft}{2} = 6 ft$

Part (a):

Now calculating the total area of the compound figure.

$\text{Total area}=\text{Area of rectangular figure}+\frac{1}{2}\times \text{Area of circle}\\\\\text{Total area}=\text{Length}\times \text{Breadth}+\frac{1}{2}\times \pi r^2$

Now putting all the given values in this formula, we get:

$\text{Total area}=(19ft\times 12ft)+\frac{1}{2}\times 3.14\times (6ft)^2\\\\\text{Total area}=284.52ft^2$

Part (b):

Now calculating the total perimeter of the compound figure.

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times \text{Circumference})\\\\\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)$

Now putting all the given values in this formula, we get:

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)\\\\\text{Total perimeter}=2\times 19ft+12ft+(\frac{1}{2}\times 2\times 3.14 \times 6ft)\\\\\text{Total perimeter}=68.84ft$