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Snowcat [4.5K]
2 years ago
15

What is the median of this data set 17,42,53,97,102,82

Mathematics
2 answers:
Zina [86]2 years ago
6 0
67.5 ... Hope I helped! :D brainliest? 
rewona [7]2 years ago
5 0
Answer = 67.5

To solve this you put the number in order so (17 42 53 82 97 102) then you count them off by removing them left to right, first 17, then 102, then 42, then 97, then you are left with 2 numbers in the middle so you average them by adding them together and then dividing them by 2 to get 67.5. If you are left with one in the middle then that is your answer.
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The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu
PSYCHO15rus [73]

Answer:

a) I(95,50) = 73.19 degrees

b) I_{T}(95,50) = -7.73

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

a) Calculate I at (T ,H) = (95, 50).

I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19 degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is I_{T}(T,H). So

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H

I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73

8 0
3 years ago
0.52+0.15=0.52+x????
pychu [463]
What I did is to add 0.52
+0.15
then try to find what could equal the same amount with 0.52
4 0
3 years ago
Read 2 more answers
Which of the following transformations are used when transforming the graph of the parent function...
hram777 [196]

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3. 3rd transformation is vertical stretch of the function y=-\log_5(x-6) by a factor of 2 to get the function y=-2\log_5(x-6).

Only last two are present in options, then

answer: C and D.

5 0
2 years ago
Peter has 3200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed a
salantis [7]

Answer:

A = 640000\,yd^{2}

Step-by-step explanation:

Expression for the rectangular area and perimeter are, respectively:

A (x,y) = x\cdot y

3200\,yd = 2\cdot (x+y)

After some algebraic manipulation, area expression can be reduce to an one-variable form:

y = 1600 -x

A (x) = x\cdot (1600-x)

The first derivative of the previous equation is:

\frac{dA}{dx}= 1600-2\cdot x

Let the expression be equalized to zero:

1600-2\cdot x=0

x = 800

The second derivative is:

\frac{d^{2}A}{dx^{2}} = -2

According to the Second Derivative Test, the critical value found in previous steps is a maximum. Then:

y = 800

The maximum area is:

A = (800\,yd)\cdot (800\,yd)

A = 640000\,yd^{2}

8 0
3 years ago
Read 2 more answers
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I am Lyosha [343]

Answer:

$0.79

Explanation:

1.58/2= 0.79

8 0
2 years ago
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