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Kaylis [27]
3 years ago
11

What is 4b+4=22 linear equation​

Mathematics
1 answer:
o-na [289]3 years ago
4 0

Answer:

b=4.5

Step-by-step explanation:

4b+4=22

4b=22-4

4b=18

b=4.5

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Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).
lesya [120]

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\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)

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\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r

=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt

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Complete the square in the quadratic term of the integrand: t^2-2t+2=(t-1)^2+1=(1-t)^2+1, then in the integral we substitute u=1-t:

\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt

\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du

Make another substitution of v=u^2:

\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv

Integrate by parts, taking

r=v+1\implies\mathrm dr=\mathrm dv

\mathrm ds=e^v\,\mathrm dv\implies s=e^v

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\implies-e=f(1,1,1)-2

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3 0
3 years ago
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I am Lyosha [343]
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So, let us suppose that the measures are, 3k, 7k, 8k.
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180°.

3k+7k+8k=180
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k= 10

Hence, the measures are,
30°, 70°, and 80°.
As all the angles are acute, so is the triangle.
6 0
3 years ago
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