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Alekssandra [29.7K]
3 years ago
12

The equation for a circle is (x-2)2+(y+3)2=9, what is the center of the circle?​

Mathematics
1 answer:
ki77a [65]3 years ago
4 0

Answer:

(2, -3)

Step-by-step explanation:

Compare the given  (x-2)2+(y+3)2=9 to the standard equation

                                 (x - h)^2 + (y - k)^2 = r^2.

It becomes obvious that h = 2, k = -3 and r = 3.

The center of this circle is (h, k):  (2, -3).

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Will Identify the outlier in the data set. 77, 73, 78, 78, 71, 75, 120, 75, 77, 72, 75, 70 The outlier is​
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Answer:

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Step-by-step explanation:

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Choose the equation below that represents the line passing through the point (1, -4) with a slope of 1/2
tatiyna

For this case we have that by definition, the line equation of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the statement we have:

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Thus, the equation is of the form:

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Finally, the equation is of the form:

y = \frac {1} {2} x- \frac {9} {2}

Answer:

y = \frac {1} {2} x- \frac {9} {2}

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