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3 years ago

The equation for a circle is (x-2)2+(y+3)2=9, what is the center of the circle?

Mathematics

1 answer:

ki77a [65]3 years ago

4 0

Answer:

(2, -3)

Step-by-step explanation:

Compare the given (x-2)2+(y+3)2=9 to the standard equation

(x - h)^2 + (y - k)^2 = r^2.

It becomes obvious that h = 2, k = -3 and r = 3.

The center of this circle is (h, k): (2, -3).

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The equation for a circle is (x-2)2+(y+3)2=9, what is the center of the circle?​

The equation for a circle is (x-2)2+(y+3)2=9, what is the center of the circle?