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harkovskaia [24]
4 years ago
12

Solve for x. 3x+ 6= 2

Mathematics
2 answers:
a_sh-v [17]4 years ago
8 0

Answer:

-4/3

Step-by-step explanation:

mash [69]4 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ We need to isolate x

3x + 6 = 2

Subtract 6 from both sides:

3x = 2 - 6

3x = -4

Divide both sides by 3:

x = -4/3

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Find the sum of 5x-y and (2xy+xy)
devlian [24]
Since neither 5x nor -y has a "like term" in <span>2xy+xy, the sum of these quantities is simply    

</span><span>2xy+xy + 5x - y = 3xy + 5x - y

You might want to write this as  y(3x -1) + 5x. </span>
8 0
3 years ago
Use an algebraic approach to solve the problem.
qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0
3 years ago
# 15. Q. Find the area of the trapezoid
harina [27]
Answer:
219.96 yd²

Explanation:
The area of the trapezoid can be calculated using the following rule:
Area of trapezoid = \frac{b1 + b2}{2} * h
where:
b1 is the length of the first base
b2 is the length of the second base
h is the height

Now, in the given we have:
b1 = 15.8 yd
b2 = 21.8 yd
h = 11.7 yd

Substitute with the givens in the above equation to get the area as follows:
area = \frac{15.8 + 21.8}{2}  * 11.7 = 219.96 yd^2

Hope this helps :)
7 0
3 years ago
A fast-food restaurant was selling 7 boxes of chicken nuggets for $25.90. A competing restaurant was selling 3 boxes of chicken
Svetlanka [38]

Answer:

The competing company is better

7 for 25.90 vs. 7 for 25.83

Step-by-step explanation:

Since it's 3 for 11.07

we need to see how much higher the price will get at 7, so divde 11.07 by 3 then double the price.

3.69 per box for competing company

11.07*2 = 22.14

22.14 + 3.69= 25.83

3 0
3 years ago
HOW do you decide which of two numbers is greater when:
Yakvenalex [24]
1. Both numbers and positive

2. to compare fractions to see which is more and which is less

3.
The solution will have the same sign as the number with the highest absolute value.
8 0
3 years ago
Read 2 more answers
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