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Marina CMI [18]
3 years ago
11

HOW do you decide which of two numbers is greater when:

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0
1. Both numbers and positive

2. to compare fractions to see which is more and which is less

3.
The solution will have the same sign as the number with the highest absolute value.
Karo-lina-s [1.5K]3 years ago
4 0

explanation: any number with a negative sign which is ( - ) is smaller than 0

and a number without a sign next to it is positive

a number line can show you both negative and positive to draw it

for example

__________________

-5 -4 -3 -2 -1 0 1 2 3 4 5

you can see we start from the left with the negative numbers

if you add a positive and a negative sign  to get the answer is the biggest number ik negative is always the smallest listen look at it like there is no signs and you see which one is the biggest then take that one

ex.

4+(-5)= -1

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Describe the rotation of J
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Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
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  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

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