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DanielleElmas [232]
3 years ago
13

At a children's party a 2 litre bottle of club orange is served in 125 ml cups. How many full cups of club orange can be served

from the full bottle?
Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

16 cups.

Step-by-step explanation:

A liter is 1000 ml. 2000 ml is equal to 2 liters, so divide 2000 by 125 and you get your answer.

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Help me answer this please. Jdjfj
Lubov Fominskaja [6]
First, find the area of the large rectangle (25*18=450) then find the area of the small square (7.5^2=56.25) finally subtract the small square from the large rectangle
3 0
4 years ago
In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

b = 0.938

g(t) = 10000(0.938)^t

3 0
4 years ago
Which equation represents an exponential function that passes through the point (2, 36)?
sesenic [268]

Answer:

The exponential function that passes through (2,36) is:

f(x)=4\times 3^x.

Step-by-step explanation:

We are asked to find which function passes through the point (2,36).

i.e. we will put the input value '2' in the following given functions and check which gives the output value as '36'.

1)

f(x)=4\times 3^x

now we put x=2.

f(2)=4\times 3^2\\\\f(2)=4\times 9\\\\f(2)=36

hence option 1 is correct.

2)

f(x)=4\times x^3

Now we put x=2.

f(2)=4\times 2^3\\\\f(2)=4\times 8\\\\f(2)=32

Hence, option 2 is incorrect.

3)

f(x)=6\times 3^x

Now we put x=2

f(2)=6\times 3^2\\\\f(2)=6\times 9\\\\f(x)=54

Hence, option 3 is incorrect.

4)

f(x)=6\times x^3

Now we put x=2.

f(2)=6\times 2^3\\\\f(2)=6\times 8\\\\f(2)=48

Hence, option 4 is incorrect.

Hence, option 1) is correct.

i.e. The exponential function that passes through (2,36) is:

f(x)=4\times 3^x

6 0
3 years ago
Read 2 more answers
Set up an equation and solve the following problem.
nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

<u>Again</u>

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

<u>For Dave</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, t = \dfrac{\textrm d miles}{\textrm s miph}

Or, t = \dfrac{\textrm 210 miles}{\textrm s miph}

<u>For Kent</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, T = \dfrac{\textrm D miles}{\textrm S miph}

Or, T = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

∵ Time taken by both is same

So, t = T

Or,  \dfrac{\textrm 210 miles}{\textrm s miph} = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = \dfrac{840}{20}

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0
3 years ago
A sales representative was paid a base salary of $77 per week. He was also paid a commission of 11 percent on everything he sold
mario62 [17]
Your answer is $594 for that week
3 0
3 years ago
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