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Nimfa-mama [501]
3 years ago
7

Write an equation of the line perpendicular to the given line that contains P.

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0

Answer:

Step-by-step explanation:

perp. -5

y + 7 = -5(x - 4)

y + 7 = -5x + 20

y = -5x + 13

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0.008 is 1/10 of what decimal?
Bas_tet [7]
The answer is .1 or .10
6 0
3 years ago
Jasmine tossed a coin 20 times. It lands on heads 14 times and tails 6 times. What is the relative frequency of landing on tails
Snowcat [4.5K]

Answer:

The relative frequency of landing on tails is 0.3.

Step-by-step explanation:

The relative frequency of an outcome A is:

The number of trials in which the outcome A happened divided by the total number of trials.

In this problem, we have that:

20 coin tosses, so 20 trials. On 6, it landed on tails.

6/20 = 0.3

This means that the relative frequency of landing on tails is 0.3.

4 0
3 years ago
{(3,-2), (4,-2),(5,-2), (6,-2)} is this a function
irga5000 [103]

Answer:

{(3,-2), (4,-2),(5,-2), (6,-2)}  this relation is not a function.

4 0
2 years ago
What does w and y equal?
Keith_Richards [23]
W+y=25 and 9.95w+11.5y=276.65
solve for w in equation one:
w+y=25
w=25-y
then substitute w in equation two and solve for y:
9.95w+11.5y=276.65
9.95(25-y)+11.5y=276.65
1.55y+248.75=276.65
1.55y+248.75-248.75=276.65-248.75
1.55y=27.9
1.55y/1.55=27.9/1.55
y=27.9/1.55=18
y=18
then substitute y=18 into the first equation to solve for x:
w+y=25
rewrite as w=25-y y=18
w=25-18
w=7
then are answer is w=7 and y=18
5 0
3 years ago
A grocery store chain has been tracking data on the number of shoppers that use coupons. The data shows that 71% of all shoppers
mariarad [96]

Answer: (0.685, 0.735)

Explanation:

First, we will compute the confidence level of the given:

\text{ Confidence Level }=\frac{36}{40}\times100\%=90\%

They gave us a margin of error of 0.025. From the given, we know that p=71%=0.71.

The confidence interval would then be:

\begin{gathered} (p-E,p+E) \\ =(0.71-0.025,0.71+0.025) \\ =(0.685,0.735) \end{gathered}

Therefore, the confidence interval would then be (0.685, 0.735)

8 0
1 year ago
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