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3 years ago

Write an equation of the line perpendicular to the given line that contains P.

Mathematics

1 answer:

lara31 [8.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

perp. -5

y + 7 = -5(x - 4)

y + 7 = -5x + 20

y = -5x + 13

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The Orchard Cafe has found that about 3% of the diners who make reservations don't show up. If 83 reservations have been made, h

daser333 [38]

Answer:

$\mu = 80.51\\\sigma = 1.56$

Step-by-step explanation:

We are given the following information in the question:

Percentage of of the diners who make reservations don't show up = 3%

Number of reservations = 83

Thus, we are given a binomial distribution with n = 83 and p = 0.97

$X\sim \text{ Binom}(p = 0.97, n = 83)$

$\mu = np = (83)(0.97) = 80.51$

Around 81 people can be expected to show up.

$\sigma = \sqrt{np(1-p)} = \sqrt{(83)(0.97)(1-0.97)} = 1.5541 \approx 1.56$

The standard deviation of this distribution is 1.56

6 0

3 years ago

How do I solve this

hichkok12 [17]

You wanna find a common denominator so put the problem like this

3 1/3.< You wanna take 3 (denominator)
And times it
By 5 then you wanna take the 5. - 2 2/5.< (deniminator) and times it by 3.
____ Your common denominator is 15

now it will look like this

3 1/15

-2 2/15
———-

Now subtract. You will need to borrow 1 from 3 since you cant subtract 2 by 1 so the 3 will become a 2 and the 1 will be come 11 and here you can subtract so this will be your answer.

2 11/15

-2 2/15
-———-
0 9/15

Thats your official answer 9/15 hope I helped :)

4 0

3 years ago

A film start at 17:15 and finish at 1 hour and 45 minutes later. what time did it finish?

vova2212 [387]

It ended at 19:00 or at 7 pm

4 0

2 years ago

31.75 as a improper and mixed fraction

Aleksandr [31]

31.75 as an improper fraction is 127/4. The mixed number fraction is 31 3/4.

3 0

3 years ago

The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of

Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

6 0

2 years ago