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GalinKa [24]
3 years ago
6

How many factors does 76 has ?​

Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer:

Positive factors of 76 are 1, 2, 4, 19, 38, and 76. Thus, it has 6 positive factors.

Step-by-step explanation:

myrzilka [38]3 years ago
6 0

Answer:

about 6 positive factors, including 1, 2, 4, 19, 38, and 76

Step-by-step explanation:

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I am going 60 miles away and I am driving 40 miles per hour the whole way how long will it take me to get there
andrezito [222]

if you are driving 40 miles per hour

1 hour = 40 miles


60-40 = 20 miles left

20/40 = 0.5

1+0.5 = 1.5 total hours

8 0
3 years ago
Plssssssssssssssssssssssssssssssssssssss
solniwko [45]

Answer:

  c.  quadrilateral

Step-by-step explanation:

All of the sides are different lengths, so the quadrilateral cannot be a parallelogram, rhombus, or square.

Its best descriptor is <em>parallelogram</em>.

_____

A <em>parallelogram</em> has opposite sides parallel and congruent. A <em>rhombus</em> also has adjacent sides congruent. A <em>square</em> is a special case of rhombus in which the corner angles are right angles.

5 0
2 years ago
What is (x+6)(x+4)(x-3) expand and simplify
mestny [16]

Answer:

x³ + 7x² - 6x - 72

Step-by-step explanation:

Given

(x + 6)(x + 4)(x - 3) ← expand the second and third factor, that is

(x + 4)(x - 3)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x - 3) + 4(x - 3) ← distribute both parenthesis

= x² - 3x + 4x - 12 ← collect like terms

= x² + x - 12

Now multiply this by (x + 6) in the same way

(x + 6)(x² + x - 12)

= x(x² + x - 12) + 6(x² + x - 12) ← distribute both parenthesis

= x³ + x² - 12x + 6x² + 6x - 72 ← collect like terms

= x³ + 7x² - 6x - 72

7 0
3 years ago
The results of a common standardized test used in psychology research is designed so that the population mean is 155 and the sta
galina1969 [7]

Answer:

The value <em>155</em> is zero standard deviations from the [population] mean, because \\ x = \mu, and therefore \\ z = 0.

Step-by-step explanation:

The key concept we need to manage here is the z-scores (or standardized values), and we can obtain a z-score using the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

  • z is the <em>z-score</em>.
  • x is the <em>raw score</em>: an observation from the normally distributed data that we want <em>standardize</em> using [1].
  • \\ \mu is the <em>population mean</em>.
  • \\ \sigma is the <em>population standard deviation</em>.

Carefully looking at [1], we can interpret it as <em>the distance from the mean of a raw value in standard deviations units. </em>When the z-score is <em>negative </em>indicates that the raw score, <em>x</em>, is <em>below</em> the population mean, \\ \mu. Conversely, a <em>positive</em> z-score is telling us that <em>x</em> is <em>above</em> the population mean. A z-score is also fundamental when determining probabilities using the <em>standard normal distribution</em>.

For example, think about a z-score = 1. In this case, the raw score is, after being standardized using [1], <em>one standard deviation above</em> from the population mean. A z-score = -1 is also one standard deviation from the mean but <em>below</em> it.

These standardized values have always the same probability in the <em>standard normal distribution</em>, and this is the advantage of using it for calculating probabilities for normally distributed data.

A subject earns a score of 155. How many standard deviations from the mean is the value 155?

From the question, we know that:

  • x = 155.
  • \\ \mu = 155.
  • \\ \sigma = 50.

Having into account all the previous information, we can say that the raw score, <em>x = 155</em>, is <u><em>zero standard deviations units from the mean.</em></u> <u><em>The subject   earned a score that equals the population mean.</em></u> Then, using [1]:

\\ z = \frac{x - \mu}{\sigma}

\\ z = \frac{155 - 155}{50}

\\ z = \frac{0}{50}

\\ z = 0

As we say before, the z-score "tells us" the distance from the population mean, and in this case this value equals zero:  

\\ x = \mu

Therefore

\\ z = 0

So, the value 155 is zero standard deviations <em>from the [population] mean</em>.

5 0
3 years ago
Using your calculator, find the proportion of observations from a standard normal distribution that satisfies the following stat
emmainna [20.7K]
<span>Look at your table for a Z value of 1.55. The numbers on the far left column are your z values. See the 1.5 row, then move over to the 0.05 column to make it 1.55.
You'll see 0.9394.
That's the area under the normal curve from 1.55 to negative infinity.
But you wanted the area under the curve greater than 1.55.
Take 1-0.9394=0.0606.
You subtract from 1 because you know that the area under the whole curve is 1, so it gives you the area you need.</span>
3 0
3 years ago
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