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2 years ago

7

An oak tree is 1.5×103 centimeters tall. Which unit of measurement is most appropriate to measure this height? kilometers feet i

nches millimeters

1 answer:

Softa [21]2 years ago

7 0

Answer:

I think the correct answer is feet

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Dwayne has a wrench set with the socket sizes of 1, 1/2, 1/4, 1/8, 1/16 what would the next size be?

lukranit [14]

Notice that the denominator is a multiplied by 2 for each fraction.

1/1•2 = 1/2

1 /2•2 = 1/4

1/4•2 = 1/8

1/8•2 = 1/16

1/16•2 =1/32

The next size is 1/32.

8 0

2 years ago

Given that f ( x ) = 5 x − 5 and g ( x ) = 4 x , evaluate g ( g ( − 2 ) )

Stels [109]

Answer:

g(g(-2))

g(-8)

-32

This is the correct solution

8 0

3 years ago

Please hurry i will mark brainliest

Ksivusya [100]

Answer:

Q (8,0)

R (8,9)

S (5,0)

Step-by-step explanation:

I counted how many places is each point away from the line and then I counted the same amount of places on the other side in order to find the reflected angle.

3 0

3 years ago

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$

= $1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}$

= 0.6865

3 0

3 years ago

You split $1500 between two savings accounts one pays 4%interest and the other pays 5% after one year you have earned $69.50 in

ANTONII [103]

Answer:

Step-by-step explanation:

Use the basic simple interest formula:

P * r * t = I and put the info into a table with those variables along the top, formig the columns we need:

P * r * t = I

Acct 1

Acct 2

If we have a total of 1500 to split up between 2 accounts, we put x amount of money into one and then have 1500-x left to put into the other. We will fill those in along with the interest rates in decimal form and the time of 1 year:

P * r * t = I

Acct 1 x .04 1

Acct 2 1500-x .05 1

Looking at the formula we are told that Prt = I, so we will multiply P times r times t and fill in the I column:

P * r * t - I

Acct 1 x .04 1 .04x

Acct 2 1500-x .05 1 .05(1500-x)

The total Interest earned by the addition of the interest earned from both accounts is 69.50. So we add the interest column together and set it equal to 69.50:

.04x + .05(1500 - x) = 69.50 and

.04x + 75 - .05x = 69.50 and

-.01x = -5.5 so

x = 550

That's how much money is in the account earning 4% interest.

7 0

2 years ago