Question

F(x)=x^4+3, g(x)=x-7 and h(x)=square root of x then f(g(h(x))=

Answer 1

Answer:

x² - 28x√x + 294x - 1372√x + 2404

Step-by-step explanation:

f(x) = $x^{4}$ + 3

g(x) = x - 7

h(x) = √x

f(g(h(x))) - ?

g(h(x)) = √x - 7

f(g(h(x))) = $(\sqrt{x} -7) ^{4}$ + 3 = ( √x - 7 )² × ( √x - 7 )² + 3 =

= (x - 14√x + 49)(x - 14√x + 49) + 3 =

= x² - 14x√x + 49x - 14x√x + 196x - 686√x + 49x - 686√x + 2401 + 3 =

=  x² - 28x√x + 294x - 1372√x + 2404