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Oliga [24]
4 years ago
10

The distance versus time graph for Object A and Object B are shown. Which object moves with changing speed?

Physics
1 answer:
Nadya [2.5K]4 years ago
6 0

Answer:

<em>Both: Object A and Object B, because different distances are traveled in the same time interval</em>

Explanation:

<u>Constant Speed Motion </u>

An object is said to have constant speed it travels same distances at the same time intervals. For example, an object who travels 4 meters in 2 seconds has a constant speed if it also travels 6 meters in 3 seconds and 10 meters in 5 seconds. The constant speed is 2 m/s.

We can see in the image provided two graphs of distance vs time of two objects. If they were traveling at a constant speed, that graph should be a single line (increasing, decreasing of horizontal). None of the graphs show a line, which indicates the object some times travels more or less distance in a given time interval than in other equal time intervals. Thus, the answer is the last option:

Both: Object A and Object B, because different distances are traveled in the same time interval

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A rock is thrown from the top of a 20-m building at an angle of 53° above the horizontal. If the horizontal range of the throw
NemiM [27]

Answer:

28.5 m/s

18.22 m/s

Explanation:

h = 20 m, R = 20 m, theta = 53 degree

Let the speed of throwing is u and the speed with which it strikes the ground is v.

Horizontal distance, R = horizontal velocity x time

Let t be the time taken

20 = u Cos 53 x t

u t = 20/0.6 = 33.33 ..... (1)

Now use second equation of motion in vertical direction

h = u Sin 53 t - 1/2 g t^2

20 = 33.33 x 0.8 - 4.9 t^2     (ut = 33.33 from equation 1)

t = 1.17 s

Put in equation (1)

u = 33.33 / 1.17 = 28.5 m/s

Let v be the velocity just before striking the ground

vx = u Cos 53 = 28.5 x 0.6 = 17.15 m/s

vy = uSin 53 - 9.8 x 1.17

vy = 28.5 x 0.8 - 16.66

vy = 6.14 m/s

v^2 = vx^2 + vy^2 = 17.15^2 + 6.14^2

v = 18.22 m/s

6 0
3 years ago
Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a
skelet666 [1.2K]

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

where,

W = Work Done = ?

F = Force = 151 N

d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

<u>W = 1418.9 J = 1.418 KJ</u>

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hope this helps

mark brainliest  :)

6 0
3 years ago
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