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balandron [24]
3 years ago
5

Atoms with a low ionization energy give up their outer valence electrons with

Physics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

a. true

Explanation:

i think

that my answer

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Holes are being steadily injected into a region of n-type silicon (connected to other devices, the details of which are not impo
Tems11 [23]

Complete Question

The  complete question is shown on the first  uploaded image

Answer:

The  value  is  J_n  =  -0.864 \  A/cm^2

Explanation:

Generally for an n-type semiconductor the current density is mathematically represented  as

         J_n  =  -q * d_p  *  \frac{d p_{n_o}}{d_w}

Here  p_{n_o} is mathematically represented as

          p_{n_o}  = \frac{n_i^2}{n_d}

=>      p_{n_o}  = \frac{(1.5*10^{10})^2}{10^{16}}

=>      p_{n_o}  = 2.25 *10^{4} \  cm^{-3}

So

    d p_{n_o} =  P_n0 - p_{n_o}

From the diagram  P_n0  =  10^8 * p_{n_o}

=>  P_n0  =  10^8 * (2.25 *10^{4} )

So

   d p_{n_o} =  10^8 * (2.25 *10^{4} ) - 2.25 *10^{4}

      d p_{n_o} =  2.25 *10^{12} cm^{-3}

So  from  J_n  =  -q * d_p  *  \frac{d p_{n_o}}{d_w}

substitute

    1.60 *10^{-19} \  C for  q  and  w_2 =50 nm =  50*10^{-9} m  =  5*10^{-6} cm

and from the diagram  w_1 =0 \ cm

So

    J_n  =  -1.60 *10^{-19} *12 *  \frac{2.25 *10^{12} }{ 5*10^{-6} - 0 }

    J_n  =  -0.864 \  A/cm^2

6 0
3 years ago
What is another word for a change in velocity/change in time
inna [77]

Answer:

acceleration

Explanation:

acceleration =velocity final-velocity initial /time

5 0
3 years ago
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A young man heaves a 6.5 kg rock at a velocity of 6.9 m/s. What is the kinetic energy of the rock?
earnstyle [38]

Answer:

Hope it will help you a lot.

7 0
2 years ago
a 0.05-kg starts from rest at a height of 0.95m. assuming no friction, what is the kinetic energy of the car when it reaches the
Alex73 [517]
Fhubugukhkbjhvlfipy0iy ft
3 0
3 years ago
To introduce you to the concept of escape velocity for a rocket. the escape velocity is defined to be the minimum speed with whi
Mama L [17]
A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R) 

This is the expression for escape velocity. 
3 0
3 years ago
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