Answer:
3.06 seconds time passes before the watermelon has the same velocity
watermelon going at speed 59.9 m/s
watermelon traveling when it hits the ground at speed is 79.19 m/s
Explanation:
given data
height = 320 m
speed = 30 m/s
to find out
How much time passes before the watermelon has the same velocity and How fast is the watermelon going and How fast is the watermelon traveling
solution
we will use here equation of motion that is
v = u + at ....................1
here v is velocity 30 m/s and u is initial speed i.e zero and a is acceleration i.e 9.8 m/s²
put the value and find time t
30 = 0 + 9.8 (t)
t = 3.06 s
so 3.06 seconds time passes before the watermelon has the same velocity
and
we know superman cover distance is = velocity × time
so distance = 30 × t
and distance formula for watermelon is
distance = ut + 0.5×a×t² .............2
here u is initial speed i.e 0 and a is acceleration i.e 9.8 m/s² and h is 30 × t
30 × t = 0 + 0.5×9.8×t²
t = 6.12 s
so by equation 1
v = u + at
v = 0 + 9.8 ( 6.12)
v = 59.9 m/s
so watermelon going at speed 59.9 m/s
and
watermelon traveling speed formula is by equation of motion
v² - u² = 2as ......................3
here v is speed and u is initial speed i.e 0 and a is acceleration i.e 9.8 m/s² and s is distance i.e 320 m
v² - 0 = 2(9.8) 320
v = 79.19 m/s
so watermelon traveling when it hits the ground at speed is 79.19 m/s
