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ivanzaharov [21]
3 years ago
13

I need help setting it up and solving it but mostly setting it all up please and thank you ?!!!i need help asap!!!!!

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
This is the work that I did. Hope it helps

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At midnight what temperature is -6C. At midday the temperature is -9C. By how much did the temperature rise ?
Zielflug [23.3K]

Answer:

It didn’t go up, it went down 3 degrees

Step-by-step explanation:

It’s negative degrees so the less negative it is the higher it is.

6 0
3 years ago
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What is an irrational number​
postnew [5]

In mathematics, the irrational numbers are all the real numbers which are not rational numbers, the latter being the numbers constructed from ratios of integers.

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4 years ago
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If h = 9 units and r = 5 units, then what is the volume of the cone shown above?
dexar [7]

Answer:

Answer = 235.5

Step-by-step explanation:

Cone volume formula is V = 1/3 * pi * r^2 * h

V = 1/3 * 3.14 * 5^2 * 9

V = 235.5

6 0
3 years ago
Why do I have to learn all of this if I'm gonna be a Rockstar when I'm older? I'm not gonna sing about geometry. or use algebra
Scorpion4ik [409]
Imo you only need to be taught the basic of math and other things like geometry and algebra should be optional, although math is a core class along english/language arts which is why it’s necessary
5 0
3 years ago
Read 2 more answers
I don’t understand how to do this
schepotkina [342]

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

4 0
3 years ago
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