Answer:
- an = 2·(4/5)^(n-1)
- 2, 8/5, 32/25, 128/125
Step-by-step explanation:
The sum of an infinite geometric series is ...
S = a1/(1 -r)
where r is the common ratio. The sum will only exist if |r| < 1.
The problem statement tells us S = 10 and a1 = 2, so we have ...
10 = 2/(1 -r)
r = 1 -2/10 = 4/5
So the n-th term of the series is ...
an = a1·r^(n-1)
an = 2·(4/5)^(n-1)
For values of n = 1 to 4, the terms are ...
2, 8/5, 32/25, 128/125
Answer:
1350 cm³
Step-by-step explanation:
we have given that,
• Height of A = 10 cm.
1350
• Volume of A = 400cm³.
• Height of B = 15 cm.
• Both A and B solids are similar.
from above told concept we get,
→ V(A) / V(B) = (Height of A)³ / (Height of B)³
Putting all given values we get,
→400/ V(B) = (10)³/(15)³
→400/V(B) = (1000/3375)
→ V(B) = (400*3375) / 1000
→ V(B) = (4 * 3375) / 10
→ V(B) = 1350 cm³. (Ans.)
Hence, Volume of B will be 1350 cm³.
131.7625 would be your answer here
The correct answer is 673
9+4= 13
5 turns into a 6 so it’s 6+1 = 7
3+3 = 9
<u>Question</u> : 8
<u>Question</u> : 9
<u>Question</u> : 11
<u>Question</u> : 12
Solution is in attachment ~
