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Lana71 [14]
3 years ago
12

84 people take a driving test.

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0
Answer: The probability that you select a women who passes is 1/2.

First, let's look at the men. 21 of the 84 test takers were men. If the ratio is 5:2 for failing. Then, 15 failed and 6 passes.

Second, let's look at the women. 63 of the test takers were women. If double the number passed, then 42 passed and 21 failed.

The chances that a random person was a women who passes is 42 out of 84 or 1/2.
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9.4 the tangent ratio<br> please help on #27 and 28
Ilya [14]

Answer/Step-by-step explanation:

27.

✔️Sin 23 = opp/hyp

Sin 23 = t/34

34*sin 23 = t

t = 13.3

✔️Cos 23 = adj/hyp

Cos 23 = s/34

s = 34*cos 23

s = 31.3

28.

✔️Sin 36 = opp/hyp

Sin 36 = s/5

s = 5*sin 36

s = 2.9

✔️Cos 36 = adj/hyp

Cos 36 = r/5

r = 5*cos 36

r = 4.0

29.

✔️Sin 70 = opp/hyp

Sin 70 = w/10

w = 10*sin 70

w = 9.4

✔️Cos 70 = adj/hyp

Cos 70 = v/10

v = 10*cos 70

v = 3.4

6 0
2 years ago
Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.004p=7ln⁡q−3ln⁡p+0.004p=7, where q is
olga2289 [7]
  <span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q: 

(1/q)(dq/dp) − 3/p + 0.003 = 0 
dq/dp = (3/p − 0.003)q. 

So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p. 

b) The revenue is pq. 
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1: 

3 − 0.003p = −1 
0.003p = 4 
p = 4/0.003 = 4000/3 = 1333.33</span>
8 0
3 years ago
Issuing a note payable for cash automatically results in a
Dmitry_Shevchenko [17]
Sry not sure this one is very confusing
5 0
3 years ago
Please Help me it’s geometry
mote1985 [20]

Answer:

Option C.

Step-by-step explanation:

Given: In \Delta OPQ,m\angle O=107^{\circ},m\angle P=28^{\circ}.

In \Delta OPQ,

m\angle O+m\angle P+m\angle Q=180^{\circ}    (Angle sum property)

107^{\circ}+28^{\circ}+m\angle Q=180^{\circ}

135^{\circ}+m\angle Q=180^{\circ}

m\angle Q=180^{\circ}-135^{\circ}

m\angle Q=45^{\circ}

Now,

m\angle O>m\angle Q>m\angle P

In a triangle, the greatest angle has largest opposite side and smallest angle has smallest opposite side. So, we conclude that

PQ>OP>QO

Therefore, the correct option is C.

7 0
3 years ago
the mean of a set of five numbers is 3k. when a sixth number is added to the set, the mean increases by k. what is the ratio of
Strike441 [17]

Let’s call the sum of the set of five numbers S and the sixth number N. We know the mean of the set of five numbers is 3k, so we can write the equation S/5 = 3k or S = 15k. When we add the sixth number the mean increases by k, so we can write the equations (S + N)/6 = 4k or S + N = 24k. Using S = 15k, we find that N = 9k. The ratio of the sixth number to the sum of the set of five numbers is therefore N/S = 9k/15k = 3/5.

4 0
2 years ago
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