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ankoles [38]
3 years ago
11

What are two type of minerals?

Chemistry
2 answers:
Oksana_A [137]3 years ago
7 0
Macro-minerals and trace minerals
Alik [6]3 years ago
5 0
The two kinds of minerals are: macrominerals<span> and trace minerals. Macro means "large" in Greek (and your body needs larger amounts of </span>macrominerals<span> than trace minerals). The </span>macromineral<span> group is made up of </span>calcium<span>, </span>phosphorus,magnesium<span>, sodium, </span>potassium<span>, chloride, and sulfur.</span>
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What is the name of NiI2
Marta_Voda [28]

Answer:

The name of that compound is Nickel(||)iodide

5 0
4 years ago
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You have a sample of each of the following five metals, with the mass and density
Sindrei [870]

Answer:

E) Silver, mass = 420 g, d = 10.5 g/cm.

Explanation:

Hello,

In this case, since the density is defined by:

\rho =\frac{m}{V}

Given the mass and density, we compute the volume via:

V=\rho *m

Thus, for each vase we have:

A) V=135g*2.7g/cm^3=364.5cm^3

B) V=305g*8.92g/cm^3=2720.6cm^3

C) V=240g*7.86g/cm^3=1886.4cm^3

D) V=75g*1.74g/cm^3=130.5cm^3

E) V=420g*10.5g/cm^3=4410cm^3

In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.

Best regards.

7 0
3 years ago
Brainliest Available! Thank you in advance!
liraira [26]

Answer:

  3.0×10⁻¹³ M

Explanation:

The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.

<h3>Equation</h3>

The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.

  Ksp = [Al₃⁺³]×[OH⁻]³

<h3>Solving for [Al₃⁺³]</h3>

The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.

This means the solubility product equation is ...

  Ksp = x(10⁻⁷ +3x)³

For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...

  3.0×10⁻³⁴ = x(10⁻⁷)³

Then x = [Al₃⁺³] will be ...

  [\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}

We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.

__

<em>Additional comment</em>

The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.

6 0
2 years ago
Read 2 more answers
Calculate normality and tire of KOH solution , if CN H2 C2 O4 solution , that is nessesary for titration is 0.1050 mol/1 and the
kozerog [31]

Answer:

Normality of KOH = 0.1062 N

<em>Note: The given question is not clearly stated. A related question below is answered and explained;</em>

<em> What is the NORMALITY of a solution of KOH if 45.18 mL are required to neutralize 0.3g of pure oxalic acid H2C2O4 . 2H2O?</em>

Explanation:

Equation of the reaction: 2KOH + H₂C₂O₄.2H₂O --> K₂C₂O₄ + 4H₂O

molar mass 0f KOH = 56 g/mol; molar mass of H₂C₂O₄.2H₂O = 126 g/mol

Number of moles of in 0.3 g of H₂C₂O₄.2H₂O = mass/molar mass

number of moles = 0.3 g / 126 g/mol = 0.0024 moles

From the equation of reaction, 2 moles of KOH are required to neutralize 1 mole of H₂C₂O₄.2H₂O

Number of moles of KOH required to neutralize 0.0024 moles of H₂C₂O₄.2H₂O = 2 * 0.0024 = 0.0048 moles

Molar concentration of 45.18 mL solution of KOH containing 0.0048 moles of  KOH = number of moles/volume (L)

molarity of KOH solution = (0.0048/45.18 mL) * (1000 mL/1 L) = 0.1062 mol/L

Normality = n * molarity

where is the number of moles of OH⁻ ions produces from  mole of KOH = 1

Normality of KOH = 1 * 0.1062

Normality of KOH = 0.1062 N

4 0
3 years ago
In examining a protein molecule, you discover that it has not file fed properly. Why is this alarming?
kicyunya [14]

Answer: This may result in the protein forming bonds with additional amino acids, this may result in the protein forming bonds with lipids instead of other proteins

Explanation:..

3 0
3 years ago
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