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3 years ago

Calculate the density of the rock if its mass is 360 g.

Chemistry

1 answer:

Pavel [41]3 years ago

4 0

Answer:

12.0 g/mL

Explanation:

From the question given above, the following data were obtained:

Mass of Rock = 360 g

Volume of water = 150 mL

Volume of water + Rock = 180 mL

Density of Rock =?

Next, we shall determine the volume of the rock. This can be obtained as follow:

Volume of water = 150 mL

Volume of water + Rock = 180 mL

Volume of Rock =?

Volume of Rock = (Volume of water + Rock) – (Volume of water)

Volume of Rock = 180 – 150

Volume of Rock = 30 mL

Finally, we shall determine the density of the rock as illustrated below:

Mass of Rock = 360 g

Volume of Rock = 30 mL

Density of Rock =?

Density = mass /volume

Density of Rock = 360 / 30

Density of Rock = 12.0 g/mL

Thus, the density of the rock is 12.0 g/mL

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(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW

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Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = 2.3x10⁻³M InF₃. Thus:

[In⁺³] = 2.3x10⁻³M InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M In⁺³

[F⁻] = 2.3x10⁻³M InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M In⁺³] × [7.0x10⁻³M F⁻]³ = 7.9x10⁻¹⁰

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, solubility is 6.31x10⁻⁶M

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