If a certain gas occupies a volume of 10. L when the applied pressure is 5.0 atm , find the pressure when the gas occupies a vol
1 answer:
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Answer:
Rate expression has been given below
Explanation:
According to the given equation, 1 molecule of A reacts with 1 molecule of B and produces 2 molecules of B at a time.
So, rate of disappearance of both A and B are one half of rate of appearance of B
Hence rate expression can be represented as:
where is rate of disappearance of A,
is rate of disappearance of B and
rate of appearance of C
Answer:
The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 0.602 mbar = 0.000602 bar
0.000602 bar = 0.000594 atm
(1 atm = 1.01325 bar)
i = Van't hoff factor = 1 (for non-electrolytes)
c = concentration of solute = ?
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:
The concentration of solute is
Volume of the solution = V =0.137 L
Moles of β‑Galactosidase = n
To calculate the molecular mass of solute, we use the equation:
Moles of β‑Galactosidase =
Given mass of β‑Galactosidase= 0.387 g
Putting values in above equation, we get:
Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.