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kenny6666 [7]
3 years ago
5

The point (2, –4) is reflected across the line y = –1. What are the coordinates of the image?

Mathematics
2 answers:
barxatty [35]3 years ago
8 0
(2,-3) that's the answer
Brilliant_brown [7]3 years ago
7 0

Answer:

its (2,2)

Step-by-step explanation:

You might be interested in
Factor completly 4x^2 +8x -5
DaniilM [7]

∑ Hey, jillianwagler ⊃

Answer:

\left(2x-1\right)\left(2x+5\right)

Step-by-step explanation:

<u><em>║Given info║:</em></u>

<em>Factor completely: </em>4x^2 +8x -5

<u><em>Solution~:</em></u>

<em>Breaking the expression~:  </em>\left(4x^2-2x\right)+\left(10x-5\right)

<em>Factor out 2x from 4x² -2x : 2x(2x-1)</em>

<em>Factor out 5 from 10x - 5 : 5(2x - 1)</em>

<em>Put together: </em>=2x\left(2x-1\right)+5\left(2x-1\right)

Factor out 2x - 1: =\left(2x-1\right)\left(2x+5\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

4 0
2 years ago
F(x) = x^2 + 2x – 4<br> f(3) = ?
Ostrovityanka [42]

Answer:

11

Step-by-step explanation:

f(3)=(3)^2+2(3)-4

f(3)=9+2(3)-4

f(3)=9+6-4

f(3)=15-4

f(3)=11

8 0
3 years ago
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
How to do this problem
Dmitrij [34]

Sorry, I don’t know lol

3 0
3 years ago
Help needed thanks it greatly appretiated
Ivan

c is the correct answer of this question

5 0
2 years ago
Read 2 more answers
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