N-acetyltyrosine ethyl ester may likely have a higher Vmax.
<h3>How are the Km and Vmax of an enzyme and substrate related?</h3>
Km is inversely proportional enzyme affinity for substrate. The lower the Km, the higher the enzyme affinity for substrate and vice versa.
Vmax is the maximum velocity of the reaction when the enzyme is fully saturated with substrate.
Based on the Km values, chymotrypsin has higher affinity for N-acetyltyrosine ethyl ester, thus, N-acetyltyrosine ethyl ester may likely have a higher Vmax.
In conclusion, the Vmax is the maximum velocity of an enzyme-catalyzed reaction.
<em>Note that the complete question is given below:</em>
<em>The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8 x 10-2 M, and the Km for the reaction of chymotrypsin with N-acetyltyrosine ethyl ester is 6.6 x 10-4 M.</em>
<em>Which of the following substrates is likely to give a higher value for Vmax?</em>
Learn more about Km and Vmax at: brainly.com/question/16108691
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Answer: I would think 1/3
Step-by-step explanation:
If there are 10 large fish and half are red that would mean there is a 5/10 chance of getting a red fish from the large fish.. because there are 15 fish in total you would do 5/15 because there are 15 and 10 of those fish are large and 5 of the large fish are red. And 5/15 to its simplest form is 1/3! If this is right please give brainlist!
Answer:
where is the rest of the question?
Step-by-step explanation:
Answer:
a(6) = 37.97
Step-by-step explanation:
If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is
a(n) = 5*r^(n - 1).
Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97
Answer:
B
Step-by-step explanation:
