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Readme [11.4K]
2 years ago
10

Megan purchased a new gadget for her technology hobby. She plans to sell it sometime in the future, however, its value depreciat

es monthly. The expression below shows the depreciated sales value of the gadget: 2020 – 22m What does the second term of the expression represent?
Mathematics
1 answer:
ElenaW [278]2 years ago
5 0

Answer:

The second term defines the value that will be depreciated by the rate of 22 units for m months.

Step-by-step explanation:

Given is :

The value of the gadget after 'm' months = 2020 - 22m

This expression tells us that, each month Meghan's gadget's price falls by 22 units from the original value.

The original value of the gadget is 2020 units.

Therefore, the constant term (2020 )of the expression represents the original value of the gadget,

And the second term defines the value that will be depreciated by the rate of 22 units for m months. And m defines the number of months Meghan will keep the gadget.

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Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

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2 years ago
If M is the midpoint of XY, find the coordinates of X if M(-3,-1) and Y(-8,6)
vova2212 [387]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
X&({{ a}}\quad ,&{{ b}})\quad 
%  (c,d)
Y&({{ -8}}\quad ,&{{ 6}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

\bf \left( \cfrac{-8+a}{2}~,~\cfrac{6+b}{2} \right)=\stackrel{M}{(-3,-1)}\implies 
\begin{cases}
\cfrac{-8+a}{2}=-3\\\\
-8+a=-6\\
\boxed{a=2}\\
----------\\
\cfrac{6+b}{2}=-1\\\\
6+b=-2\\
\boxed{b=-8}
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2 years ago
What is the common denominator for 1 2/3 and 3/4
Elena L [17]

Answer:

The answer is 12

Step-by-step explanation:

Multiply 1*3

Add 2 to the number

Change the first number to 5/3

Multiply 3*4

3 0
2 years ago
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

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P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

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If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

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3 years ago
If x equals 12, find the value of x2 ?
Anna [14]

Answer:

24

Step-by-step explanation:

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